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(B) The work done per unit volume in stretching an elastic wire is known as the elastic potential energy density.By Hooke's Law,within the elastic lim

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$\frac{1}{2} 	imes Stress 	imes Strain$

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(B) The work done per unit volume in stretching an elastic wire is known as the elastic potential energy density.By Hooke's Law,within the elastic limit,the stress is proportional to the strain.The work done $dW$ in stretching a wire of length $L$ and cross-sectional area $A$ by a small displacement $dl$ is $dW = F \cdot dl$.Since $F = Stress 	imes A$ and $dl = Strain 	imes L$,the work done per unit volume is given by the integral of stress with respect to strain.$u = \int_{0}^{\epsilon} \sigma \, d\epsilon = \int_{0}^{\epsilon} Y\epsilon \, d\epsilon = \frac{1}{2} Y \epsilon^2 = \frac{1}{2} 	imes Stress 	imes Strain$.Therefore,the correct option is $B$.

The work done in stretching an elastic wire per unit volume is

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The work done per unit volume in stretching a wire is :-

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