The work done in stretching an elastic wire per unit volume is
$Stress$ $ \times $ $Strain$
$\frac{1}{2} \times $$Stress$ $ \times $$Strain$
$2 \times {\rm{strain}} \times {\rm{stress}}$
$Stress$$/$$Strain$
A stretched rubber has
$K$ is the force constant of a spring. The work done in increasing its extension from ${l_1}$ to ${l_2}$ will be
What is called elastic potential energy ? Write its different formulas.
When shearing force is applied on a body, then the elastic potential energy is stored in it. On removing the force, this energy
When a force is applied on a wire of uniform cross-sectional area $3 \times {10^{ - 6}}\,{m^2}$ and length $4m$, the increase in length is $1\, mm.$ Energy stored in it will be $(Y = 2 \times {10^{11}}\,N/{m^2})$